4-7 在一個數組中實現兩個堆疊 (20分)
阿新 • • 發佈:2019-01-27
本題要求在一個數組中實現兩個堆疊。
函式介面定義:
Stack CreateStack( int MaxSize );
bool Push( Stack S, ElementType X, int Tag );
ElementType Pop( Stack S, int Tag );
其中Tag是堆疊編號,取1或2;MaxSize堆疊陣列的規模;Stack結構定義如下:
typedef int Position;
struct SNode {
ElementType *Data;
Position Top1, Top2;
int MaxSize;
};
typedef struct SNode *Stack;
注意:如果堆疊已滿,Push函式必須輸出“Stack Full”並且返回false;如果某堆疊是空的,則Pop函式必須輸出“Stack Tag Empty”(其中Tag是該堆疊的編號),並且返回ERROR。
裁判測試程式樣例:
#include <stdio.h>
#include <stdlib.h>
#define ERROR 1e8
typedef int ElementType;
typedef enum { push, pop, end } Operation;
typedef enum { false, true } bool;
typedef int Position;
struct SNode {
ElementType *Data;
Position Top1, Top2;
int MaxSize;
};
typedef struct SNode *Stack;
Stack CreateStack( int MaxSize );
bool Push( Stack S, ElementType X, int Tag );
ElementType Pop( Stack S, int Tag );
Operation GetOp(); /* details omitted */
void PrintStack( Stack S, int Tag ); /* details omitted */
int main()
{
int N, Tag, X;
Stack S;
int done = 0;
scanf("%d", &N);
S = CreateStack(N);
while ( !done ) {
switch( GetOp() ) {
case push:
scanf("%d %d", &Tag, &X);
if (!Push(S, X, Tag)) printf("Stack %d is Full!\n", Tag);
break;
case pop:
scanf("%d", &Tag);
X = Pop(S, Tag);
if ( X==ERROR ) printf("Stack %d is Empty!\n", Tag);
break;
case end:
PrintStack(S, 1);
PrintStack(S, 2);
done = 1;
break;
}
}
return 0;
}
/* 你的程式碼將被嵌在這裡 */
輸入樣例:
5
Push 1 1
Pop 2
Push 2 11
Push 1 2
Push 2 12
Pop 1
Push 2 13
Push 2 14
Push 1 3
Pop 2
End
輸出樣例:
Stack 2 Empty
Stack 2 is Empty!
Stack Full
Stack 1 is Full!
Pop from Stack 1: 1
Pop from Stack 2: 13 12 11
#include <stdio.h>
#include <stdlib.h>
#define ERROR 1e8
typedef int ElementType;
typedef enum { push, pop, end } Operation;
typedef enum { false, true } bool;
typedef int Position;
struct SNode {
ElementType *Data;
Position Top1, Top2;
int MaxSize;
};
typedef struct SNode *Stack;
Stack CreateStack( int MaxSize );
bool Push( Stack S, ElementType X, int Tag );
ElementType Pop( Stack S, int Tag );
Operation GetOp(){
char a[5];
scanf("%s",a);
if(strcmp(a,"Push")==0) return push;
if(strcmp(a,"Pop")==0) return pop;
if(strcmp(a,"End")==0) return end;
}
void PrintStack( Stack S, int Tag ){
if(Tag==1){
printf("Pop from Stack %d: ",Tag);
while((S->Top1)!=-1){
printf("%d ",S->Data[(S->Top1)--]);
}
putchar('\n');
}else{
printf("Pop from Stack %d: ",Tag);
while((S->Top2)!=S->MaxSize){
printf("%d ",S->Data[(S->Top2)++]);
}
putchar('\n');
}
}
int main()
{
int N, Tag, X;
Stack S;
int done = 0;
scanf("%d", &N);
S = CreateStack(N);
while ( !done ) {
switch( GetOp() ) {
case push:
scanf("%d %d", &Tag, &X);
if (!Push(S, X, Tag)) printf("Stack %d is Full!\n", Tag);
break;
case pop:
scanf("%d", &Tag);
X = Pop(S, Tag);
if ( X==ERROR ) printf("Stack %d is Empty!\n", Tag);
break;
case end:
PrintStack(S, 1);
PrintStack(S, 2);
done = 1;
break;
}
}
return 0;
}
Stack CreateStack( int MaxSize ){
Stack S = (Stack)malloc(sizeof(struct SNode));
S->MaxSize = MaxSize;
S->Data = (ElementType *)malloc(sizeof(ElementType)*MaxSize);
S->Top2 = MaxSize;
S->Top1 = -1;
return S;
}
bool Push( Stack S, ElementType X, int Tag ){
if(S == NULL)
return false;
if((S->Top1 + 1) == S->Top2){
printf("Stack Full\n");
return false;
}
if(1 == Tag){
S->Data[++(S->Top1)] = X;
return true;
}
else if (2 == Tag){
S->Data[(--S->Top2)] = X;
return true;
}
return false;
}
ElementType Pop( Stack S, int Tag ){
if(S == NULL)
return ERROR;
if(1 == Tag){
if(-1 == S->Top1){
printf("Stack %d Empty\n", Tag);
return ERROR;
}
return S->Data[(S->Top1)--];
}else if(2 == Tag){
if(S->MaxSize == S->Top2){
printf("Stack %d Empty\n", Tag);
return ERROR;
}
return S->Data[(S->Top2)++];
}
return ERROR;
}
題目連結: