靜態區間內第k大(小)的數
阿新 • • 發佈:2019-01-25
整體二分
//#include<bits/stdc++.h> #include<cstdio> #include<algorithm> #include<iostream> #include<cstring> using namespace std; const int N=200000; struct data{int l,r,id,k;}s[N],s1[N],s2[N]; int n,m,cnt,i,tot,ans[N],bit[N],a[N],b[N]; void add(int x,int v){while(x<=n)bit[x]+=v,x+=x&-x;} int sum(int x,int res=0){while(x)res+=bit[x],x-=x&-x;return res;} void CDQ(int l,int r,int L,int R){ if(L>R)return; int q1=0,q2=0,mid=l+r>>1,i; if(l==r){for(i=L;i<=R;++i)if(s[i].id>0)ans[s[i].id]=b[l];return;} for(i=L;i<=R;++i) if(s[i].id<0){ if(s[i].l>mid) add(s[i].r,1),s2[q2++]=s[i]; else s1[q1++]=s[i]; } else{ if(sum(s[i].r)-sum(s[i].l-1)>=s[i].k) s2[q2++]=s[i]; else s[i].k=s[i].k-(sum(s[i].r)-sum(s[i].l-1)),s1[q1++]=s[i]; } for(i=L;i<=R;++i) if(s[i].id<0&&s[i].l>mid)add(s[i].r,-1); memcpy(s+L,s1,sizeof(data)*q1); memcpy(s+L+q1,s2,sizeof(data)*q2); CDQ(l,mid,L,L+q1-1);CDQ(mid+1,r,L+q1,R); } int main(){ for(scanf("%d%d",&n,&m),i=1;i<=n;++i) scanf("%d",a+i),b[i]=a[i]; sort(b+1,b+n+1);tot=unique(b+1,b+n+1)-b-1; for(i=1;i<=n;++i) s[++cnt]=data{int(lower_bound(b+1,b+tot+1,a[i])-b),i,-1}; for(i=1;i<=m;++i) ++cnt,scanf("%d%d%d",&s[cnt].l,&s[cnt].r,&s[cnt].k),s[cnt].id=i; for(CDQ(1,tot,1,cnt),i=1;i<=m;++i) printf("%d\n",ans[i]); } //7 3 //1 3 5 2 6 7 4 //4 4 1 //2 5 3 //1 7 3