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MySQL多表查詢例項詳解【連結查詢、子查詢等】

本文例項講述了MySQL多表查詢。分享給大家供大家參考,具體如下:

準備工作:準備兩張表,部門表(department)、員工表(employee)

create table department(
id int,name varchar(20)
);
create table employee(
id int primary key auto_increment,name varchar(20),sex enum('male','female') not null default 'male',age int,dep_id int
);

#插入資料
insert into department values
(200,'技術'),(201,'人力資源'),(202,'銷售'),(203,'運營');
insert into employee(name,sex,age,dep_id) values
('egon','male',18,200),('alex','female',48,201),('wupeiqi',38,('yuanhao',28,202),('nvshen',('xiaomage',204)
;

# 查看錶結構和資料
mysql> desc department;
+-------+-------------+------+-----+---------+-------+
| Field | Type    | Null | Key | Default | Extra |
+-------+-------------+------+-----+---------+-------+
| id  | int(11)   | YES |   | NULL  |    |
| name | varchar(20) | YES |   | NULL  |    |
+-------+-------------+------+-----+---------+-------+
2 rows in set (0.19 sec)

mysql> desc employee;
+--------+-----------------------+------+-----+---------+----------------+
| Field | Type         | Null | Key | Default | Extra     |
+--------+-----------------------+------+-----+---------+----------------+
| id   | int(11)        | NO  | PRI | NULL  | auto_increment |
| name  | varchar(20)      | YES |   | NULL  |        |
| sex  | enum('male','female') | NO  |   | male  |        |
| age  | int(11)        | YES |   | NULL  |        |
| dep_id | int(11)        | YES |   | NULL  |        |
+--------+-----------------------+------+-----+---------+----------------+
5 rows in set (0.01 sec)

mysql> select * from department;
+------+--------------+
| id  | name     |
+------+--------------+
| 200 | 技術     |
| 201 | 人力資源   |
| 202 | 銷售     |
| 203 | 運營     |
+------+--------------+
4 rows in set (0.02 sec)

mysql> select * from employee;
+----+----------+--------+------+--------+
| id | name   | sex  | age | dep_id |
+----+----------+--------+------+--------+
| 1 | egon   | male  |  18 |  200 |
| 2 | alex   | female |  48 |  201 |
| 3 | wupeiqi | male  |  38 |  201 |
| 4 | yuanhao | female |  28 |  202 |
| 5 | nvshen  | male  |  18 |  200 |
| 6 | xiaomage | female |  18 |  204 |
+----+----------+--------+------+--------+
6 rows in set (0.00 sec)

ps:觀察兩張表,發現department表中id=203部門在employee中沒有對應的員工,發現employee中id=6的員工在department表中沒有對應關係。

一多表連結查詢

SELECT 欄位列表
FROM 表1 INNER|LEFT|RIGHT JOIN 表2
ON 表1.欄位 = 表2.欄位;

(1)先看第一種情況交叉連線:不適用任何匹配條件。生成笛卡爾積.--->重複最多

mysql> select * from employee,department;
+----+----------+--------+------+--------+------+--------------+
| id | name   | sex  | age | dep_id | id  | name     |
+----+----------+--------+------+--------+------+--------------+
| 1 | egon   | male  |  18 |  200 | 200 | 技術     |
| 1 | egon   | male  |  18 |  200 | 201 | 人力資源   |
| 1 | egon   | male  |  18 |  200 | 202 | 銷售     |
| 1 | egon   | male  |  18 |  200 | 203 | 運營     |
| 2 | alex   | female |  48 |  201 | 200 | 技術     |
| 2 | alex   | female |  48 |  201 | 201 | 人力資源   |
| 2 | alex   | female |  48 |  201 | 202 | 銷售     |
| 2 | alex   | female |  48 |  201 | 203 | 運營     |
| 3 | wupeiqi | male  |  38 |  201 | 200 | 技術     |
| 3 | wupeiqi | male  |  38 |  201 | 201 | 人力資源   |
| 3 | wupeiqi | male  |  38 |  201 | 202 | 銷售     |
| 3 | wupeiqi | male  |  38 |  201 | 203 | 運營     |
| 4 | yuanhao | female |  28 |  202 | 200 | 技術     |
| 4 | yuanhao | female |  28 |  202 | 201 | 人力資源   |
| 4 | yuanhao | female |  28 |  202 | 202 | 銷售     |
| 4 | yuanhao | female |  28 |  202 | 203 | 運營     |
| 5 | nvshen  | male  |  18 |  200 | 200 | 技術     |
| 5 | nvshen  | male  |  18 |  200 | 201 | 人力資源   |
| 5 | nvshen  | male  |  18 |  200 | 202 | 銷售     |
| 5 | nvshen  | male  |  18 |  200 | 203 | 運營     |
| 6 | xiaomage | female |  18 |  204 | 200 | 技術     |
| 6 | xiaomage | female |  18 |  204 | 201 | 人力資源   |
| 6 | xiaomage | female |  18 |  204 | 202 | 銷售     |
| 6 | xiaomage | female |  18 |  204 | 203 | 運營     |

(2)內連線:只連線匹配的行,以雙方為基準

#找兩張表共有的部分,相當於利用條件從笛卡爾積結果中篩選出了匹配的結果
#department沒有204這個部門,因而employee表中關於204這條員工資訊沒有匹配出來
mysql> select employee.id,employee.name,employee.age,employee.sex,department.name from employee inner join department on employee.dep_id=department.id;
+----+---------+------+--------+--------------+
| id | name  | age | sex  | name     |
+----+---------+------+--------+--------------+
| 1 | egon  |  18 | male  | 技術     |
| 2 | alex  |  48 | female | 人力資源   |
| 3 | wupeiqi |  38 | male  | 人力資源   |
| 4 | yuanhao |  28 | female | 銷售     |
| 5 | nvshen |  18 | male  | 技術     |
+----+---------+------+--------+--------------+
5 rows in set (0.00 sec)

#上述sql等同於
mysql> select employee.id,department.name from employee,department where employee.dep_id=department.id;

(3)外連結之左連線:優先顯示左表全部記錄

#以左表為準,即找出所有員工資訊,當然包括沒有部門的員工
#本質就是:在內連線的基礎上增加左邊有,右邊沒有的結果
mysql> select employee.id,department.name as depart_name from employee left join department on employee.dep_id=department.id;
+----+----------+--------------+
| id | name   | depart_name |
+----+----------+--------------+
| 1 | egon   | 技術     |
| 5 | nvshen  | 技術     |
| 2 | alex   | 人力資源   |
| 3 | wupeiqi | 人力資源   |
| 4 | yuanhao | 銷售     |
| 6 | xiaomage | NULL     |
+----+----------+--------------+
6 rows in set (0.00 sec)

(4) 外連結之右連線:優先顯示右表全部記錄

#以右表為準,即找出所有部門資訊,包括沒有員工的部門
#本質就是:在內連線的基礎上增加右邊有,左邊沒有的結果
mysql> select employee.id,department.name as depart_name from employee right join department on employee.dep_id=department.id;
+------+---------+--------------+
| id  | name  | depart_name |
+------+---------+--------------+
|  1 | egon  | 技術     |
|  2 | alex  | 人力資源   |
|  3 | wupeiqi | 人力資源   |
|  4 | yuanhao | 銷售     |
|  5 | nvshen | 技術     |
| NULL | NULL  | 運營     |
+------+---------+--------------+
6 rows in set (0.00 sec)

(5) 全外連線:顯示左右兩個表全部記錄(瞭解)

#外連線:在內連線的基礎上增加左邊有右邊沒有的和右邊有左邊沒有的結果
#注意:mysql不支援全外連線 full JOIN
#強調:mysql可以使用此種方式間接實現全外連線

語法:select * from employee left join department on employee.dep_id = department.id
union all
select * from employee right join department on employee.dep_id = department.id;

 mysql> select * from employee left join department on employee.dep_id = department.id
     union
    select * from employee right join department on employee.dep_id = department.id
      ;
+------+----------+--------+------+--------+------+--------------+
| id  | name   | sex  | age | dep_id | id  | name     |
+------+----------+--------+------+--------+------+--------------+
|  1 | egon   | male  |  18 |  200 | 200 | 技術     |
|  5 | nvshen  | male  |  18 |  200 | 200 | 技術     |
|  2 | alex   | female |  48 |  201 | 201 | 人力資源   |
|  3 | wupeiqi | male  |  38 |  201 | 201 | 人力資源   |
|  4 | yuanhao | female |  28 |  202 | 202 | 銷售     |
|  6 | xiaomage | female |  18 |  204 | NULL | NULL     |
| NULL | NULL   | NULL  | NULL |  NULL | 203 | 運營     |
+------+----------+--------+------+--------+------+--------------+
7 rows in set (0.01 sec)

#注意 union與union all的區別:union會去掉相同的紀錄

二、符合條件連線查詢

以內連線的方式查詢employee和department表,並且employee表中的age欄位值必須大於25,即找出年齡大於25歲的員工以及員工所在的部門

select employee.name,department.name from employee inner join department
  on employee.dep_id = department.id
  where age > 25;

三、子查詢

#1:子查詢是將一個查詢語句巢狀在另一個查詢語句中。
#2:內層查詢語句的查詢結果,可以為外層查詢語句提供查詢條件。
#3:子查詢中可以包含:IN、NOT IN、ANY、ALL、EXISTS 和 NOT EXISTS等關鍵字
#4:還可以包含比較運算子:= 、 !=、> 、<等

(1)帶in關鍵字的子查詢

#查詢平均年齡在25歲以上的部門名
select id,name from department
  where id in
    (select dep_id from employee group by dep_id having avg(age) > 25);
# 檢視技術部員工姓名
select name from employee
  where dep_id in
    (select id from department where name='技術');
#檢視不足1人的部門名
select name from department
  where id not in
    (select dep_id from employee group by dep_id);

(2)帶比較運算子的子查詢

#比較運算子:=、!=、>、>=、<、<=、<>
#查詢大於所有人平均年齡的員工名與年齡
mysql> select name,age from employee where age > (select avg(age) from employee);
+---------+------+
| name  | age |
+---------+------+
| alex  |  48 |
| wupeiqi |  38 |
+---------+------+
#查詢大於部門內平均年齡的員工名、年齡

思路:

(1)先對員工表(employee)中的人員分組(group by),查詢出dep_id以及平均年齡。
(2)將查出的結果作為臨時表,再對根據臨時表的dep_id和employee的dep_id作為篩選條件將employee表和臨時表進行內連線。
(3)最後再將employee員工的年齡是大於平均年齡的員工名字和年齡篩選。

mysql> select t1.name,t1.age from employee as t1
       inner join
      (select dep_id,avg(age) as avg_age from employee group by dep_id) as t2
      on t1.dep_id = t2.dep_id
      where t1.age > t2.avg_age;
+------+------+
| name | age |
+------+------+
| alex |  48 |

(3)帶EXISTS關鍵字的子查詢

#EXISTS關字鍵字表示存在。在使用EXISTS關鍵字時,內層查詢語句不返回查詢的記錄。而是返回一個真假值。True或False
#當返回True時,外層查詢語句將進行查詢;當返回值為False時,外層查詢語句不進行查詢
#department表中存在dept_id=203,Ture
mysql> select * from employee where exists (select id from department where id=200);
+----+----------+--------+------+--------+
| id | name   | sex  | age | dep_id |
+----+----------+--------+------+--------+
| 1 | egon   | male  |  18 |  200 |
| 2 | alex   | female |  48 |  201 |
| 3 | wupeiqi | male  |  38 |  201 |
| 4 | yuanhao | female |  28 |  202 |
| 5 | nvshen  | male  |  18 |  200 |
| 6 | xiaomage | female |  18 |  204 |
+----+----------+--------+------+--------+
#department表中存在dept_id=205,False
mysql> select * from employee where exists (select id from department where id=204);
Empty set (0.00 sec)

更多關於MySQL相關內容感興趣的讀者可檢視本站專題:《MySQL查詢技巧大全》、《MySQL常用函式大彙總》、《MySQL日誌操作技巧大全》、《MySQL事務操作技巧彙總》、《MySQL儲存過程技巧大全》及《MySQL資料庫鎖相關技巧彙總》

希望本文所述對大家MySQL資料庫計有所幫助。