C語言-6-7 在一個數組中實現兩個堆疊 (20 分)
阿新 • • 發佈:2022-04-02
本題要求在一個數組中實現兩個堆疊。
函式介面定義:
Stack CreateStack( int MaxSize );
bool Push( Stack S, ElementType X, int Tag );
ElementType Pop( Stack S, int Tag );
其中Tag
是堆疊編號,取1或2;MaxSize
堆疊陣列的規模;Stack
結構定義如下:
typedef int Position;
struct SNode {
ElementType *Data;
Position Top1, Top2;
int MaxSize;
};
typedef struct SNode *Stack;
注意:如果堆疊已滿,Push
函式必須輸出“Stack Full”並且返回false;如果某堆疊是空的,則Pop
函式必須輸出“Stack Tag Empty”(其中Tag是該堆疊的編號),並且返回ERROR。
裁判測試程式樣例:
#include <stdio.h>
#include <stdlib.h>
#define ERROR 1e8
typedef int ElementType;
typedef enum { push, pop, end } Operation;
typedef enum { false, true } bool;
typedef int Position;
struct SNode {
ElementType *Data;
Position Top1, Top2;
int MaxSize;
};
typedef struct SNode *Stack;
Stack CreateStack( int MaxSize );
bool Push( Stack S, ElementType X, int Tag );
ElementType Pop( Stack S, int Tag );
Operation GetOp(); /* details omitted */
void PrintStack( Stack S, int Tag ); /* details omitted */
int main()
{
int N, Tag, X;
Stack S;
int done = 0;
scanf("%d", &N);
S = CreateStack(N);
while ( !done ) {
switch( GetOp() ) {
case push:
scanf("%d %d", &Tag, &X);
if (!Push(S, X, Tag)) printf("Stack %d is Full!\n", Tag);
break;
case pop:
scanf("%d", &Tag);
X = Pop(S, Tag);
if ( X==ERROR ) printf("Stack %d is Empty!\n", Tag);
break;
case end:
PrintStack(S, 1);
PrintStack(S, 2);
done = 1;
break;
}
}
return 0;
}
/* 你的程式碼將被嵌在這裡 */
輸入樣例:
5
Push 1 1
Pop 2
Push 2 11
Push 1 2
Push 2 12
Pop 1
Push 2 13
Push 2 14
Push 1 3
Pop 2
End
輸出樣例:
Stack 2 Empty
Stack 2 is Empty!
Stack Full
Stack 1 is Full!
Pop from Stack 1: 1
Pop from Stack 2: 13 12 11
1 Stack CreateStack( int MaxSize ) 2 { 3 Stack stack=(Stack)malloc(sizeof(structSNode)); 4 stack->Data=(int *)malloc(sizeof(ElementType)*MaxSize); 5 stack->Top1=-1; 6 stack->Top2=MaxSize; 7 stack->MaxSize=MaxSize; 8 return stack; 9 } 10 11 bool Push( Stack S, ElementType X, int Tag ){ 12 if(S==NULL) 13 return false; 14 if(S->Top1+1 == S->Top2) 15 {printf("Stack Full\n"); 16 return false;} 17 if(Tag==1) 18 {S->Data[++S->Top1] = X;//++x即x先+1後形成s【x】 19 return true;} 20 else{ 21 S->Data[--S->Top2] = X; 22 return true; 23 } 24 } 25 ElementType Pop( Stack S, int Tag ){ 26 if(S==NULL) 27 return false; 28 if(Tag==1){ 29 if(S->Top1==-1) 30 {printf("Stack %d Empty\n",Tag); 31 return ERROR;} 32 return S->Data[S->Top1--];//x--即先形成s【x】再-1 33 } 34 35 else 36 { 37 if(S->Top2==S->MaxSize) 38 {printf("Stack %d Empty\n",Tag); 39 return ERROR;} 40 } 41 return S->Data[S->Top2++]; 42 }