[Python]小甲魚Python視頻第030課(文件系統:介紹一個高大上的東西)課後題及參考解答
阿新 • • 發佈:2019-03-10
sep 方式 str 視頻格式 min ets 要求 遍歷文件夾 所有
# -*- coding: utf-8 -*- """ Created on Fri Mar 8 15:49:32 2019 @author: Administrator """ """ 動動手: 0. 編寫一個程序,統計當前目錄下每個文件類型的文件數,程序實現如圖: 1. 編寫一個程序,計算當前文件夾下所有文件的大小,程序實現如圖 2. 編寫一個程序,用戶輸入文件名以及開始搜索的路徑,搜索該文件是否存在。如遇到文件夾,則進入文件夾繼續搜索,程序實現如圖 3. 編寫一個程序,用戶輸入開始搜索的路徑,查找該路徑下(包含子文件夾內)所有的視頻格式文件(要求查找mp4 rmvb, avi的格式即可),並把創建一個文件(vedioList.txt)存放所有找到的文件的路徑,程序實現如圖: 4. 編寫一個程序,用戶輸入關鍵字,查找當前文件夾內(如果當前文件夾內包含文件夾,則進入文件夾繼續搜索)所有含有該關鍵字的文本文件(.txt後綴),要求顯示該文件所在的位置以及關鍵字在文件中的具體位置(第幾行第幾個字符),程序實現如圖: """ import os #動動手0 def count_file_format_num(): file_folder = "F:\\drink_c_02010121\\test9"; result_dict = dict(); result_dict[‘無後綴名文件‘] = 0 result_dict[‘文件夾‘] = 0 filelist = os.listdir(file_folder); for each in filelist: each_full_name = file_folder+‘\\‘+each if os.path.isfile(each_full_name): if ‘.‘ in each: file_name = each.split(‘.‘); if file_name[-1] in result_dict.keys(): result_dict[file_name[-1]] += 1; else: result_dict[file_name[-1]] = 1; else: result_dict[‘無後綴名文件‘] +=1; else: result_dict[‘文件夾‘] +=1; print(‘ [%s] 中共有[%d]類文件‘ % (file_folder,len(result_dict.keys()))) for key in result_dict.keys(): print("該文件夾下共有類型為【%s】的文件【%d】個" % (‘.‘+key,result_dict[key])) #動動手1 def get_file_size(): file_folder = "F:\\drink_c_02010121\\test9\\"; result_dict = dict(); filelist = os.listdir(file_folder); for each in filelist: each_file_full_name = file_folder + os.sep + each; result_dict[each] = os.path.getsize(each_file_full_name) for key in result_dict.keys(): print(‘%s 【%dBytes】‘ % (key,result_dict[key])); #動動手2: def find_file_in_dir(folder_path,target_file_name): filelist = os.listdir(folder_path) for each in filelist: #each_full_name = folder_path +‘\\‘+ each each_full_name = folder_path + os.sep + each; if each == target_file_name and os.path.isfile(each_full_name): print(each_full_name) if os.path.isdir(each_full_name): find_file_in_dir(each_full_name,target_file_name) #folder_path = input(‘請輸入待查找的初始目錄:‘) #target_file_name = input(‘請輸入需要查找的目標文件:‘) #find_file_in_dir(folder_path,target_file_name) #動動手3 #非遞歸方式,只能到本層和下一層 def get_spec_file_num(): file_folder = "F:\\drink_c_02010121\\test9" result_list = list(); filelist = os.listdir(file_folder) valid_suffix = [‘rar‘,‘h‘]; for each in filelist: if os.path.isdir(file_folder+‘\\‘+each): sub_file_folder = file_folder +‘\\‘ + each; sub_file_list = os.listdir(sub_file_folder) for sub_each in sub_file_list: filename = sub_each.split(‘.‘); if len(filename) >=2 and filename[-1] in valid_suffix: result_list.append(sub_file_folder+‘\\‘+sub_each); else: filename = each.split(‘.‘); if len(filename) >= 2 and filename[-1] in valid_suffix: result_list.append(file_folder+‘\\‘+each); f_out = open(‘file_list.txt‘,‘w‘); for each in result_list: f_out.writelines(each+‘\n‘); f_out.close(); #遞歸方式,遞歸遍歷子文件夾 result_list = list() valid_suffix = [‘rar‘,‘h‘]; def get_spec_file_num_res( folder_path ): global result_list global valid_suffix filelist = os.listdir(folder_path) for each in filelist: if os.path.isdir(folder_path+‘\\‘+each): get_spec_file_num_res(folder_path+‘\\‘+each); else: filename = each.split(‘.‘); if len(filename) >= 2 and filename[-1] in valid_suffix: result_list.append(folder_path+‘\\‘+each); #動動手4: #0.遍歷文件夾獲得以.txt結尾的文件 #1.獲取.txt文件的內容,獲取關鍵字的存在與否的信息並打印出來 def get_key_word_info_of_txt_file( folder_path,key_word): file_list = os.listdir(folder_path); for each in file_list: each_full_name = folder_path + ‘\\‘ + each if os.path.isdir(each_full_name): get_key_word_info_of_txt_file(each_full_name,key_word) elif each.endswith(‘.txt‘) and os.path.isfile(each_full_name): file_obj = open(each_full_name,‘r‘) file_valid = 0; lines_count = 0; for each_line in file_obj: lines_count += 1; locs = []; #lines = []; str_count = each_line.count(key_word); index = 0; while str_count!=0: index = each_line.find(key_word,index) locs.append(index); index = index + 1; str_count -= 1; if len(locs)!=0: file_valid = 1 if file_valid == 0 else 2; if file_valid == 1: print(‘文件【%s】中出現關鍵字【%s】:‘ % (each_full_name,key_word)) print(‘關鍵字【%s】出現在 %d 行,第%s 個位置‘ %(key_word,lines_count,locs)); file_obj.close() get_key_word_info_of_txt_file( ‘C:\\Users\\fengs\Desktop\\SVN_TEST\\Python\\小甲魚課後題\\測試文件夾‘,‘1‘) #count_file_format_num() #get_file_size() #get_spec_file_num_res(‘F:\\drink_c_02010121\\test9‘) #for each in result_list: # print(each) """ 需要註意的問題: 1. 目錄分隔符可以用python提供的 os.sep 來代替,以適應不同的操作系統 2. 我的代碼都是用的絕對路徑,所以不存在切換目錄的問題 3. 若要用相對路徑,相關的常量: os.curdir -----> 當前目錄 os.sep -----> 目錄分隔符 os.chdir() -----> 切換工作目錄 os.pardir -----> 當前工作目錄的上一層目錄 os.getcwd() -----> 當前工作目錄的絕對路徑 """
[Python]小甲魚Python視頻第030課(文件系統:介紹一個高大上的東西)課後題及參考解答