1. 程式人生 > >八週 專案3 分數類中的運算子過載

八週 專案3 分數類中的運算子過載

/*
* 程式的版權和版本宣告部分:
* Copyright (c) 2013, 煙臺大學計算機學院
* All rights reserved.
* 檔名稱:test.cpp
* 作    者:趙加響
* 完成日期:2014年 4月 17日
* 程式輸出:
* 問題分析:略
* 演算法設計:略
*/
#include <iostream>
using namespace std;
class CFraction
{
private:
    int nume;  // 分子
    int deno;  // 分母
public:
    //建構函式及運算子過載的函式宣告
    CFraction(int nu=0,int de=1);
    void setTime(int nu,int de);
    void display();
    void simplify();
    bool operator < (CFraction &c);
    bool operator > (CFraction &c);
    bool operator <= (CFraction &c);
    bool operator >= (CFraction &c);
    bool operator == (CFraction &c);
    bool operator != (CFraction &c);
    CFraction operator + (CFraction &c);
    CFraction operator - (CFraction &c);
    CFraction operator * (CFraction &c);
    CFraction operator / (CFraction &c);
};
//過載函式的實現及用於測試的main()函式
CFraction::CFraction(int nu,int de)
{
    nume=nu;
    deno=de;
}
void CFraction::display()
{
    cout<<nume<<"/"<<deno<<endl;
}
void CFraction::simplify()
{
    int d,n,r;
    d=deno;
    n=nume;
    while(r=d%n)
    {
        d=n;
        n=r;
    }
    deno/=n;
    nume/=n;
    if(deno<0)
    {
        deno=-deno;
        nume=-nume; //借鑑賀老師的
    }
}
bool CFraction::operator < (CFraction &c)
{
    while(deno==c.deno)
    {
    if(nume<c.nume)
    return true;
    else
    return false;
    }
    while(deno!=c.deno)
    {
        if(nume*c.deno<deno*c.nume)
        return true;
    else
    return false;
    }
}
bool CFraction::operator > (CFraction &c)
{
    while(deno==c.deno)
    {
    if(nume>c.nume)
    return true;
    else
    return false;
    }
    while(deno!=c.deno)
    {
        if(nume*c.deno>deno*c.nume)
        return true;
    else
    return false;
    }
}
bool CFraction::operator <= (CFraction &c)
{
    if(*this>c)return false;
    return true;
}
bool CFraction::operator >= (CFraction &c)
{
    if(*this<c)return false;
    return true;
}
bool CFraction::operator == (CFraction &c)
{
    if(*this<=c&&*this>=c)return true;
    return false;
}
bool CFraction::operator != (CFraction &c)
{
    if(*this==c)return false;
    return true;
}
CFraction CFraction::operator + (CFraction &c)
{
    int de,nu;
    if(deno==c.deno)
    {
        nu=nume+c.nume;
        de=deno;
    }
    else
    nu=nume*c.deno+deno*c.nume;
    de=deno*c.deno;
    CFraction c0(nu,de);
    c0.simplify();
    return c0;
}
CFraction CFraction::operator - (CFraction &c)
{
    int de,nu;
    if(deno==c.deno)
    {
        nu=nume-c.nume;
        de=deno;
    }
    else
    nu=nume*c.deno-deno*c.nume;
    de=deno*c.deno;
    CFraction c0(nu,de);
    c0.simplify();
    return c0;
}
CFraction CFraction::operator * (CFraction &c)
{
    int de,nu;
    de=deno*c.deno;
    nu=nume*c.nume;
    CFraction c0(nu,de);
    c0.simplify();
    return c0;
}
CFraction CFraction::operator / (CFraction &c)
{
    int de,nu;
    de=deno*c.nume;
    nu=nume*c.deno;
    CFraction c0(nu,de);
    c0.simplify();
    return c0;
}
int main()
{
    CFraction c1(3,8),c2(3,7),c3,c4,c5,c6;
    cout<<"c1=";
    c1.display();
    cout<<"c2=";
    c2.display();
    cout<<"c1,c2關係為:"<<endl;;
    if(c1<c2)cout<<"c1<c2"<<endl;
    if(c1>c2)cout<<"c1>c2"<<endl;
    if (c1==c2) cout<<"c1=c2"<<endl;
    if (c1!=c2) cout<<"c1≠c2"<<endl;
    if (c1>=c2) cout<<"c1≥c2"<<endl;
    if (c1<=c2) cout<<"c1≤c2"<<endl;
    cout<<endl;
    c3=c1+c2;
    cout<<"c1+c2=";
    c3.display();
    c4=c1-c2;
    cout<<"c1-c2=";
    c4.display();
    c5=c1*c2;
    cout<<"c1*c2=";
    c5.display();
    c6=c1/c2;
    cout<<"c1/c2=";
    c6.display();
}

感悟:終於靠自己的力量做出來了,儘管其中有老師的提示,但在這一篇中博文中,我流了很多汗水,和專案2不同的是,只有個別的幾句是借鑑的。