用一條SQL語句 查詢出每門課都大於80分的學生姓名

name   kecheng   fenshu 

張三     語文            81

張三     數學            75

李四     語文            76

李四     數學            90

王五     語文            81

王五     數學           100

王五     英語            90 

select distinct name from score  where  name not in (select distinct name from score where score<=80)
 

select distinct name from student s where not exists (select * from student s2 where fenshu <= 80 and s2.name = s.name);