因為業務需求，要將多個jsonArray合併，使用scala分分鐘實現，程式碼異常簡潔。

程式碼

object test extends App{

//構造jsonArray
val obj1 = new JSONObject()
  obj1.put("name","breeze")
  obj1.put("age",22)
val obj2 = new JSONObject()
  obj2.put("name","lsw")
  obj2.put("age",20)
  obj2.put("addr","hangzhou")
//arr1有2個obj
val jsonArray1 = new
 
 JSONArray()
  jsonArray1.put(obj1)
  jsonArray1.put(obj2)
//arr2有一個obj
val jsonArray2 = new JSONArray()
  jsonArray2.put(obj2)  
//arr3為空  
val jsonArray3 = new JSONArray()

/**
* 接收引數為任意個數的String(jsonArray)
* 將其合併為一個
*/
def combineJsonArray(arrs: String*): String ={
    val jsonArray = new JSONArray()
    for
 
 (arr <- arrs){
    //排除空值
        if(StringUtils.isNotBlank(arr)){
          val jSONArray = new JSONArray(arr)
          for(i <- 0 until jSONArray.length()){
            jsonArray.put(jSONArray.getJSONObject(i))
          }
        }
    }    
    jsonArray.toString()
  }
}

//不同引數輸出
println("3args:"
 
+ combineJsonArray(jsonArray1.toString,jsonArray2.toString,jsonArray3.toString))

println("2args:"+ combineJsonArray(jsonArray1.toString,jsonArray2.toString))

println("1args:"+ combineJsonArray(jsonArray1.toString))

輸出結果

3args:[{"name":"breeze","age":22},{"name":"lsw","age":20,"addr":"hangzhou"},{"name":"lsw","age":20,"addr":"hangzhou"}]

2args:[{"name":"breeze","age":22},{"name":"lsw","age":20,"addr":"hangzhou"},{"name":"lsw","age":20,"addr":"hangzhou"}]

1args:[{"name":"breeze","age":22},{"name":"lsw","age":20,"addr":"hangzhou"}]