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php中用for巢狀迴圈解決雞兔同籠問題

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原始碼:
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<!DOCTYPE html>
<html>
	<head>
		<meta charset="UTF-8">
		<title></title>
	</head>
	<body>
		<?php
			
		$tou=40;
		for($chicken=1;$chicken<$tou;$chicken++)
		{
		    for($rabbit=1;$rabbit<$tou;$rabbit++)
		    { 
		        if(($rabbit+$chicken==$tou)&&(2*$chicken+4*$rabbit==100))
		        {
		            echo "雞有:".$chicken."只"."<br>";
		            echo "兔有:".$rabbit."只";
		            break;
		        }
		    }
		}
		?>
	</body>
</html>