給出字串分別計算出字串中數字、大小寫字母的個數。(兩種方法 getBytes( ) charAt( ) )
阿新 • • 發佈:2018-11-26
public class LetterAndNumberCount {
public static void main(String[] args) {
Count("FJJgjsgfsd543632");
count1("SFsefgdg2354354fsdf");
}
public static void Count(String str){
int A = 0;
int a = 0;
int Number = 0;
byte[] bytes = str.getBytes(); // 將字串轉為byte陣列
for(int i=0;i<bytes.length;i++){
if(bytes[i] >= 'a' && bytes[i] <= 'z'){
a++;
}else if(bytes[i]>='A' && bytes[i]<='Z'){
A++;
}else if(bytes[i]>='0' && bytes[i]<='9'){
Number ++;
}
}
System.out.println("大寫字母個數為:"+ A);
System.out.println("小寫字母個數為:"+ a);
System.out.println("數字個數為:"+ Number);
}
public static void count1(String str){
int A = 0;
int a = 0;
int Number = 0;
for(int i=0;i<str.length();i++){
char array = str.charAt(i); //便利陣列後用charAt(i)來返回指定字元然後if進行判斷
if(array >= 'a' && array <= 'z'){
a++;
}else if(array>='A' && array<='Z'){
A++;
}else if(array>='0' && array<='9'){
Number++;
}
}
System.out.println("大寫字母個數為:"+ A);
System.out.println("小寫字母個數為:"+ a);
System.out.println("數字個數為:"+ Number);
}
}