廢話不多說，直接上程式碼

    /// <summary>
    /// 分紅包
    /// </summary>
    public class RandomMoney
    {
        public RandomMoney(double totalMoney, int totalCount)
        {
            RemainMoney = totalMoney;
            RemainCount = totalCount;
        }
        /// <summary>
        /// 剩下的金額
        /// 
 
</summary>
        private double RemainMoney { get; set; }
        /// <summary>
        /// 剩下的次數
        /// </summary>
        private double RemainCount { get; set; }

        private Random r = new Random();
        /// <summary>
        /// 獲取當次紅包的金額
        /// </summary>
        /// <
 
returns></returns>
        public double GetRandomMoney()
        {
            if (RemainCount < 1)
                throw new Exception("紅包已經搶完了");

            if (RemainCount == 1)//最後一次
            {
                RemainCount--;
                return (double)Math.Round(RemainMoney * 100) / 100;
            }
            double min 
 
= 0.01;
            double max = RemainMoney / RemainCount * 2;
            double money = r.NextDouble() * max;//隨機收取本次金額
            money = money <= min ? 0.01 : money;//判斷最小值
            money = Math.Floor(money * 100) / 100;
            RemainCount--;//紅包個數遞減
            RemainMoney = RemainMoney - money;//計算剩餘金額
            return money;//返回本次領取金額
        }
    }

下面寫個demo測試一下。

    class Program
    {
        static void Main(string[] args)
        {
            double totalMoney = 200;
            int totalCount = 10;
            RandomMoney random = new RandomMoney(totalMoney, totalCount);
            for (int i = 0; i < totalCount; i++)
            {
                Console.WriteLine($"第{i + 1}個紅包:{random.GetRandomMoney()}元");
            }
            Console.ReadKey();
        }
    }

上面的案例是一個200塊錢的紅包分10份，列印結果如下

這種分紅包的方式有一個缺陷，就是  紅包的金額 <= 剩下的金額 / 剩下的次數

大家有沒有更好的分紅包方式呢