效果圖：

程式碼：

<div class="table">
                        <el-table ref="table_8" :data="saCountAvg" border style="width: 99%;" :height=winHeight :header-cell-style="tableHeaderColor" :cell-style="cellStyle" :span-method="objectSpanMethod8">
                            <el-table-column prop="
 
name" label="SA" align="center"></el-table-column>
                            <el-table-column prop="getTime" label="產值達均值線以上次數" align="center"></el-table-column>
                            <el-table-column prop="timeIndex" label="月份" align="center"></el-table-column>
                            <el-table-column prop="
 
monthlyIntervalValue" label="月度產值" align="center"></el-table-column>
                            <el-table-column prop="avgValue" label="月度均值" align="center"></el-table-column>
                        </el-table>
                    </div>

methods: {
    tableHeaderColor({ row, column, rowIndex, columnIndex }) {
        
 
if (rowIndex === 0) {
          return "color: #4f81bd;font-weight: bold ;";
        }
     },

objectSpanMethod8({ row, column, rowIndex, columnIndex }) {
        if (columnIndex === 0) {
          const _row = (this.flitterData(this.saCountAvg ).one)[rowIndex];
          const _col = _row > 0 ? 1 : 0;
          return {
            rowspan: _row,
            colspan: _col
          };
        }
        if (columnIndex === 1) {
          const _row = (this.flitterData(this.saCountAvg ).two)[rowIndex];
          const _col = _row > 0 ? 1 : 0;
          return {
            rowspan: _row,
            colspan: _col
          };
        }
      },


      flitterData(arr) {
        let spanOneArr = [],
          spanTwoArr = [],
          concatOne = 0,
          concatTwo = 0;
        arr.forEach((item, index) => {
          if (index === 0) {
            spanOneArr.push(1);
            spanTwoArr.push(1);
          } else {
            if (item.userId === arr[index - 1].userId) { //第一列需合併相同內容的判斷條件
              spanOneArr[concatOne] += 1;
              spanOneArr.push(0);
            } else {
              spanOneArr.push(1);
              concatOne = index;
            }
            if (item.getTime === arr[index - 1].getTime && item.userId === arr[index - 1].userId) {//第二列需合併相同內容的判斷條件
              spanTwoArr[concatTwo] += 1;
              spanTwoArr.push(0);
            } else {
              spanTwoArr.push(1);
              concatTwo = index;
            }
          }
        })
        return {
          one: spanOneArr,
          two: spanTwoArr,
        }
      },



}

大功告成了