基於PyQT實現區分左鍵雙擊和單擊
阿新 • • 發佈:2020-05-20
在PyQt中沒有直接提供左鍵雙擊的判斷方法,需要自己實現,其思路主要如下所示:
1、起動一個定時器,判斷在指定的時間之內,點選次數超過2次,則視為雙擊(其主要思路判斷兩次點選的時間差在預測的條件以內)
2、 起動一個定時器,判斷在指定的時間之內,點選次數超過2次,另外再獲取滑鼠點選的座標,如果前後兩次點選的座標位置,屬於同一個位置,滿足這兩個條件則判斷為雙擊(其主要思路判斷兩次點選的時間差在預測的條件以內,且點選的座標在預設的座標之內,允許存在一定的偏差)
from PyQt5.QtCore import QTimer from PyQt5 import QtCore,QtGui,QtWidgets class myWidgets(QtWidgets.QTableWidget): def __init__(self,parent=None): super(myWidgets,self).__init__(parent) self.isDoubleClick = False self.mouse = "" def mousePressEvent(self,e): # 左鍵按下 if e.buttons() == QtCore.Qt.LeftButton: QTimer.singleShot(0,lambda: self.judgeClick(e)) # 右鍵按下 elif e.buttons() == QtCore.Qt.RightButton: self.mouse = "右" # 中鍵按下 elif e.buttons() == QtCore.Qt.MidButton: self.mouse = '中' # 左右鍵同時按下 elif e.buttons() == QtCore.Qt.LeftButton | QtCore.Qt.RightButton: self.mouse = '左右' # 左中鍵同時按下 elif e.buttons() == QtCore.Qt.LeftButton | QtCore.Qt.MidButton: self.mouse = '左中' # 右中鍵同時按下 elif e.buttons() == QtCore.Qt.MidButton | QtCore.Qt.RightButton: self.mouse = '右中' # 左中右鍵同時按下 elif e.buttons() == QtCore.Qt.LeftButton | QtCore.Qt.MidButton | QtCore.Qt.RightButton: self.mouse = '左中右' def mouseDoubleClickEvent(self,e): # 雙擊 self.mouse = "雙擊" self.isDoubleClick=True def judgeClick(self,e): if self.isDoubleClick== False: self.mouse="左" else: self.isDoubleClick=False self.mouse = "雙擊"
或
from PyQt5.QtCore import QTimer from PyQt5 import QtCore,QtWidgets class myWidgets(QtWidgets.QTableWidget): def __init__(self,self).__init__(parent) self.mouse = "" self.timer=QTimer(self) self.timer.timeout.connect(self.singleClicked) def singleClicked(self): if self.timer.isActive(): self.timer.stop() self.mouse="左" def mouseDoubleClickEvent(self,e): if self.timer.isActive() and e.buttons() ==QtCore.Qt.LeftButton: self.timer.stop() self.mouse="雙擊" super(myWidgets,self).mouseDoubleClickEvent(e) def mousePressEvent(self,e): if e.buttons()== QtCore.Qt.LeftButton: self.timer.start(1000) elif e.buttons()== QtCore.Qt.RightButton: self.mouse="右" super(myWidgets,self).mousePressEvent(e)
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