技術標籤：程式設計學習SCAU

1099 [填空題]連結串列的合併

Description

下面程式建立兩個連結串列，然後將第二個連結串列合併到第一個連結串列未尾，但合併部分的程式碼未完成，請你完成這部分程式碼。

#include "stdio.h"
#include "malloc.h"
#define LEN sizeof(struct student)

struct student
{
     long num;
     int score;
     struct student *next;
};

struct student *
 
create(int n)
{ 
     struct student *head=NULL,*p1=NULL,*p2=NULL;
     int i;
     for(i=1;i<=n;i++)
     {  p1=(struct student *)malloc(LEN);
        scanf("%ld",&p1->num);    
        scanf("%d",&p1->score);    
        p1->next=NULL;
        if(i==1) head=
 
p1;
        else p2->next=p1;
        p2=p1;
      }
      return(head);
}

struct student *merge(struct student *head, struct student *head2)
{ 
_______________________
}


void print(struct student *head)
{
    struct student *p;
    p=head;
    while(p!=NULL)
    {
        printf("%8ld%8d"
 
,p->num,p->score);
        p=p->next;
        printf("\n");
    }
}

main()
{
    struct student *head, *head2;
    int n;
    long del_num;
    scanf("%d",&n); 
    head=create(n);
    print(head);
    scanf("%d",&n); 
    head2=create(n);
    print(head2);
    head = merge(head, head2);    
    print(head);
}

輸入樣例

2 （the 1st linked list, 2 students）
1 （code of no.1 studentof the 1st linked list）
98 （score of no.1 student of the 1st linked list）
7 （code of no.2 student of the 1st linked list）
99 （score of no.2 student of the 1st linked list）
1 （the 2nd linked list, 1 student）
5 （code of no.1 student of the 2nd linked list）
87 （score of no.1 student of the 2nd linked list）

輸出樣例

   1      98
   7      99
   5      87
   1      98
   7      99
   5      87

程式碼實現

struct student *merge(struct student *head, struct student *head2)
{
    struct student *p1=head;
    while(p1->next!=NULL)p1=p1->next;
    p1->next=head2;
    return head;
}