本文例項為大家分享了C語言實現洗牌與發牌遊戲的具體程式碼，供大家參考，具體內容如下

普通版

#include<stdio.h>
#include<stdlib.h>
#include<time.h>

#define SUITS 4
#define FACES 13
#define CARDS 52

void shuffle(int wDeck[][FACES]);
void send(int wDeck[][FACES],const char* wSuit[],const char* wFace[]);

void main()
{
 int deck[SUITS][FACES]={0};
 const char* suit[SUITS]={"Heart","Diamond","Club","Spade"};
 const char* face[FACES]={"Ace","Two","Three","Four","Five","Six","Seven","Eight","Nine","Ten","Jack","Queen","King"};
 
 srand(time(NULL));
 shuffle(deck);
 send(deck,suit,face);
}

void shuffle(int wDeck[][FACES])
{
 int row,column,card;

 for(card=1;card<=CARDS;card++)
 {
 row = rand() % SUITS;
 column = rand() % FACES;
 while(wDeck[row][column] != 0)
 {
 row = rand() % SUITS;
 column = rand() % FACES;
 }
 wDeck[row][column] = card;
 }
}

void send(int wDeck[][FACES],const char* wFace[])
{
 int card,row,column;
 for(card=1;card<=CARDS;card++)
 {
 for(row=0;row<SUITS;row++)
 {
 for(column=0;column<FACES;column++)
 {
 if(wDeck[row][column] == card)
 {
  printf("%5s of %-8s%c",wFace[column],wSuit[row],card % 2 ==0 ? '\n' : '\t');
 }
 }
 }
 }
}

高效能版

//先按順序填滿52個格子，再產生隨機格子相互交換

#include<stdio.h>
#include<stdlib.h>
#include<time.h>

#define CARDS 52
#define FACES 13

struct card
{
 const char* face;
 const char* suit;
};
typedef struct card Card;

void shuffle(Card *const wDeck);
void send(const Card *const wDeck);//指標常量與資料常量均不可以改變，都用const限定，*前是限定指標，*後是限定資料

void main()
{
 const char* wSuit[]={"Heart","Spade"};//指標陣列是一個數組
 const char* wFace[]={"Ace","King"};
 int i;
 Card deck[CARDS];
 for(i=0;i<CARDS;i++)
 {
 deck[i].suit = wSuit[i / FACES];
 deck[i].face = wFace[i % FACES];
 }
 
 srand(time(NULL));
 shuffle(deck);
 send(deck);
}

void shuffle(Card *const wDeck)
{
 int i,j;
 Card temp;
 for(i=0;i<CARDS;i++)
 {
 j = rand() % CARDS;
 temp = wDeck[i];
 wDeck[i] = wDeck[j];
 wDeck[j] = temp;
 }
}

void send(const Card *const wDeck)
{
 int i;
 for(i=0;i<CARDS;i++)
 {
 printf("%5s of %-8s%c",wDeck[i].face,wDeck[i].suit,(i+1) % 4 == 0 ? '\n' : '\t');
 }
}

以上就是本文的全部內容，希望對大家的學習有所幫助，也希望大家多多支援我們。