python測試開發django（25）--表單提交之post修改密碼
阿新 • • 發佈：2020-12-10
前言
跟賬號相關的功能一般是註冊，登入，修改密碼，密碼找回功能，前面實現了登入和註冊功能，本篇講下修改密碼功能實現
修改密碼html
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>修改密碼</title>
</head>
<body>
<h1>修改密碼！</h1>
<form action="" method="post">
{% csrf_token %}
<p>
使用者名稱：<input type="text" name="username",required="required">*
</p>
<p>
密碼：<input type="password" name="password",required="required">*
</p>
<p>
新密碼：<input type="password" name="new",required="required">*
</p>
<p>
{{msg}}
</p>
<p>
<input type="submit" value="確定">
</p>
</form>
</body>
</html>
views和urls
#coding:utf-8
from django.shortcuts import render
from django.http import HttpResponse
from tb.models import Users
from django.contrib.auth.hashers import make_password,check_password
def reset_pwd(request):
rs=""
if request.method=="GET":
return render(request,'chpwd.html',{'msg':rs})
if request.method=="POST":
username=request.POST.get('username')
pwd=request.POST.get("password")
new_pwd=request.POST.get("new")
if pwd==new_pwd:
rs="新密碼和舊密碼不能重複"
return render(request,'chpwd.html',{'msg':rs})
else:
#先查詢資料庫是否有此使用者名稱
user_lst=Users.objects.filter(user_name=username).first()
if not user_lst:
#沒這個使用者
rs="{}使用者未註冊".format(username)
return render(request,'chpwd.html',{'msg':rs})
else:
#如果註冊過，判斷密碼對不對
is_pwd=check_password(pwd,user_lst.pwd)
if is_pwd:
user=Users.objects.get(user_name=username)
user.pwd=make_password(new_pwd)
user.save()
rs="密碼修改成功!"
else:
rs="密碼錯誤！"
return render(request,'chpwd.html',{'msg':rs})
urls.py訪問地址
# coding:utf-8
from django.conf.urls import url
from tb import views
urlpatterns = [
# 新增使用者
url(r'^register/', views.register),
url(r'^login/', views.login),
url('^chpwd/',views.reset_pwd),
]
實現效果如下